------------------------------------------------------------------------ -- A solution to a problem posed by Venanzio Capretta ------------------------------------------------------------------------ module VenanziosProblem where open import Coinduction open import Data.Nat open import Data.Stream as Stream using (Stream; _⋎_; evens; odds; _≈_) open Stream.Stream; open Stream._≈_ open import Relation.Binary private module S {A} = Setoid (Stream.setoid A) ------------------------------------------------------------------------ -- Problem formulation -- The problem concerns functions satisfying a certain equation: rhs : {A : Set} → (Stream A → Stream A) → Stream A → Stream A rhs φ s = s ⋎ φ (evens (φ s)) SatisfiesEquation : {A : Set} → (Stream A → Stream A) → Set SatisfiesEquation φ = ∀ s → φ s ≈ rhs φ s -- The statement of the problem: Statement : Set₁ Statement = {A : Set} {φ₁ φ₂ : Stream A → Stream A} → SatisfiesEquation φ₁ → SatisfiesEquation φ₂ → ∀ s → φ₁ s ≈ φ₂ s ------------------------------------------------------------------------ -- Solution module Solution {A : Set} where infixr 5 _∷_ infix 4 _∣_∣_≈P_ _∣_∣_≈W_ infix 2 _∎ infixr 2 _≈⟨_⟩_ -- Let us first define a small language of equality proofs. -- -- m ∣ n ∣ xs ≈P ys means that xs and ys, which are streams -- generated in chunks of size 1 + m, where the outer chunk has size -- n, are equal. mutual -- Weak head normal forms of programs. data _∣_∣_≈W_ : ℕ → ℕ → Stream A → Stream A → Set where reset : ∀ {xs₁ xs₂ m} (xs₁≈xs₂ : ∞ (m ∣ suc m ∣ xs₁ ≈P xs₂)) → m ∣ 0 ∣ xs₁ ≈W xs₂ _∷_ : ∀ x {xs₁ xs₂ m n} (xs₁≈xs₂ : m ∣ n ∣ ♭ xs₁ ≈W ♭ xs₂) → m ∣ suc n ∣ x ∷ xs₁ ≈W x ∷ xs₂ -- Programs. data _∣_∣_≈P_ : ℕ → ℕ → Stream A → Stream A → Set where -- WHNFs are programs. ↑ : ∀ {m n xs₁ xs₂} (xs₁≈xs₂ : m ∣ n ∣ xs₁ ≈W xs₂) → m ∣ n ∣ xs₁ ≈P xs₂ -- Various congruences. _∷_ : ∀ x {xs₁ xs₂ m n} (xs₁≈xs₂ : m ∣ n ∣ ♭ xs₁ ≈P ♭ xs₂) → m ∣ suc n ∣ x ∷ xs₁ ≈P x ∷ xs₂ _⋎-cong_ : ∀ {xs₁ xs₂ ys₁ ys₂} (xs₁≈xs₂ : 1 ∣ 1 ∣ xs₁ ≈P xs₂) (ys₁≈ys₂ : 0 ∣ 1 ∣ ys₁ ≈P ys₂) → 1 ∣ 2 ∣ xs₁ ⋎ ys₁ ≈P xs₂ ⋎ ys₂ evens-cong : ∀ {xs₁ xs₂} (xs₁≈xs₂ : 1 ∣ 1 ∣ xs₁ ≈P xs₂) → 0 ∣ 1 ∣ evens xs₁ ≈P evens xs₂ odds-cong : ∀ {xs₁ xs₂} (xs₁≈xs₂ : 1 ∣ 2 ∣ xs₁ ≈P xs₂) → 0 ∣ 1 ∣ odds xs₁ ≈P odds xs₂ -- Equational reasoning. _≈⟨_⟩_ : ∀ xs₁ {xs₂ xs₃ m n} (xs₁≈xs₂ : m ∣ n ∣ xs₁ ≈P xs₂) (xs₂≈xs₃ : m ∣ n ∣ xs₂ ≈P xs₃) → m ∣ n ∣ xs₁ ≈P xs₃ _∎ : ∀ {n m} xs → m ∣ n ∣ xs ≈P xs -- If we have already produced 1 + n elements of the last chunk, -- then it is safe to pretend that we have only produced n -- elements. shift : ∀ {n m xs₁ xs₂} (xs₁≈xs₂ : m ∣ suc n ∣ xs₁ ≈P xs₂) → m ∣ n ∣ xs₁ ≈P xs₂ -- A variation of the statement we want to prove. goal′ : ∀ {φ₁ φ₂ xs₁ xs₂} (s₁ : SatisfiesEquation φ₁) (s₂ : SatisfiesEquation φ₂) (xs₁≈xs₂ : 0 ∣ 1 ∣ xs₁ ≈P xs₂) → 1 ∣ 1 ∣ rhs φ₁ xs₁ ≈P rhs φ₂ xs₂ -- The equality language is complete. completeW : ∀ {n m xs ys} → xs ≈ ys → m ∣ n ∣ xs ≈W ys completeW {zero} xs≈ys = reset (♯ ↑ (completeW xs≈ys)) completeW {suc n} (x ∷ xs≈ys) = x ∷ completeW (♭ xs≈ys) -- If we can prove that the equality language is sound, then the -- following lemma implies the intended result. goal : ∀ {φ₁ φ₂ xs₁ xs₂} (s₁ : SatisfiesEquation φ₁) (s₂ : SatisfiesEquation φ₂) → 0 ∣ 1 ∣ xs₁ ≈P xs₂ → 1 ∣ 1 ∣ φ₁ xs₁ ≈P φ₂ xs₂ goal {φ₁} {φ₂} {xs₁} {xs₂} s₁ s₂ xs₁≈xs₂ = φ₁ xs₁ ≈⟨ ↑ (completeW (s₁ xs₁)) ⟩ rhs φ₁ xs₁ ≈⟨ goal′ s₁ s₂ xs₁≈xs₂ ⟩ rhs φ₂ xs₂ ≈⟨ ↑ (completeW (S.sym (s₂ xs₂))) ⟩ φ₂ xs₂ ∎ -- Some lemmas about weak head normal forms. evens-congW : {xs₁ xs₂ : Stream A} → 1 ∣ 1 ∣ xs₁ ≈W xs₂ → 0 ∣ 1 ∣ evens xs₁ ≈W evens xs₂ evens-congW (x ∷ reset xs₁≈xs₂) = x ∷ reset (♯ odds-cong (♭ xs₁≈xs₂)) reflW : ∀ xs {m} n → m ∣ n ∣ xs ≈W xs reflW xs zero = reset (♯ (xs ∎)) reflW (x ∷ xs) (suc n) = x ∷ reflW (♭ xs) n transW : ∀ {xs ys zs m n} → m ∣ n ∣ xs ≈W ys → m ∣ n ∣ ys ≈W zs → m ∣ n ∣ xs ≈W zs transW (x ∷ xs≈ys) (.x ∷ ys≈zs) = x ∷ transW xs≈ys ys≈zs transW (reset xs≈ys) (reset ys≈zs) = reset (♯ (_ ≈⟨ ♭ xs≈ys ⟩ ♭ ys≈zs)) shiftW : ∀ n {m xs₁ xs₂} → m ∣ suc n ∣ xs₁ ≈W xs₂ → m ∣ n ∣ xs₁ ≈W xs₂ shiftW zero (x ∷ reset xs₁≈xs₂) = reset (♯ (x ∷ shift (♭ xs₁≈xs₂))) shiftW (suc n) (x ∷ xs₁≈xs₂) = x ∷ shiftW n xs₁≈xs₂ -- Every program can be transformed into WHNF. whnf : ∀ {xs ys m n} → m ∣ n ∣ xs ≈P ys → m ∣ n ∣ xs ≈W ys whnf (↑ xs≈ys) = xs≈ys whnf (x ∷ xs₁≈xs₂) = x ∷ whnf xs₁≈xs₂ whnf (xs₁≈xs₂ ⋎-cong ys₁≈ys₂) with whnf xs₁≈xs₂ | whnf ys₁≈ys₂ ... | x ∷ reset xs₁≈xs₂′ | y ∷ reset ys₁≈ys₂′ = x ∷ y ∷ reset (♯ (shift (♭ xs₁≈xs₂′) ⋎-cong ♭ ys₁≈ys₂′)) whnf (evens-cong xs₁≈xs₂) = evens-congW (whnf xs₁≈xs₂) whnf (odds-cong xs₁≈xs₂) with whnf xs₁≈xs₂ ... | x ∷ xs₁≈xs₂′ = evens-congW xs₁≈xs₂′ whnf (xs₁ ≈⟨ xs₁≈xs₂ ⟩ xs₂≈xs₃) = transW (whnf xs₁≈xs₂) (whnf xs₂≈xs₃) whnf (xs ∎) = reflW xs _ whnf (shift xs₁≈xs₂) = shiftW _ (whnf xs₁≈xs₂) whnf (goal′ s₁ s₂ xs₁≈xs₂) with whnf xs₁≈xs₂ ... | (x ∷ reset xs₁≈xs₂′) = x ∷ reset (♯ (goal s₁ s₂ (evens-cong (goal s₁ s₂ xs₁≈xs₂)) ⋎-cong ♭ xs₁≈xs₂′)) -- Soundness follows by a corecursive repetition of the whnf -- procedure. ⟦_⟧W : ∀ {xs ys m n} → m ∣ n ∣ xs ≈W ys → xs ≈ ys ⟦ reset ys≈zs ⟧W with whnf (♭ ys≈zs) ... | x ∷ ys≈zs′ = x ∷ ♯ ⟦ ys≈zs′ ⟧W ⟦ x ∷ ys≈zs ⟧W = x ∷ ♯ ⟦ ys≈zs ⟧W ⟦_⟧P : ∀ {xs ys m n} → m ∣ n ∣ xs ≈P ys → xs ≈ ys ⟦ xs≈ys ⟧P = ⟦ whnf xs≈ys ⟧W -- Wrapping up. solution : Statement solution s₁ s₂ s = ⟦ goal s₁ s₂ (s ∎) ⟧P where open Solution