format version = 1.0 begin solution of problem ss_cascade3 date = 14-Nov-08 08:07:38 url = http://www.cs.chalmers.se/~dag/identification // Settings for the Gennemark & Wedelin (2007) algorithm randomStarts_ = 8 1 smoothingParameter = 0.2 randomSeed = 5 // ALPHA alpha_1 = 9.83281311 alpha_2 = 1.92468881 alpha_3 = 4.56805276 // BETA beta_1 = 6.83444258 beta_2 = 1.16233029 beta_3 = 8.76000009 // G g has defaultValue = 0 g_1_3 = -0.104085938 g_2_1 = 0.457761813 g_2_4 = 0.181413459 g_3_2 = 0.946357471 // H h has defaultValue = 0 h_1_1 = 0.358329615 h_1_4 = -0.714491086 h_2_2 = 0.576926945 h_3_1 = 0.0133763273 h_3_2 = 0.564410453 h_3_3 = 0.373837391 // INITIAL VALUES variable_1 of experiment_1 has initialValue = 0.1915E+00 variable_2 of experiment_1 has initialValue = 0.4695E+00 variable_3 of experiment_1 has initialValue = 0.1107E+00 variable_1 of experiment_2 has initialValue = 0.9560E-01 variable_2 of experiment_2 has initialValue = 0.5956E+00 variable_3 of experiment_2 has initialValue = 0.6113E+00 variable_1 of experiment_3 has initialValue = 0.9191E-01 variable_2 of experiment_3 has initialValue = 0.5641E+00 variable_3 of experiment_3 has initialValue = 0.5301E+00 variable_1 of experiment_4 has initialValue = 0.4133E+00 variable_2 of experiment_4 has initialValue = 0.5768E+00 variable_3 of experiment_4 has initialValue = 0.9654E-01 variable_1 of experiment_5 has initialValue = 0.5797E+00 variable_2 of experiment_5 has initialValue = 0.3833E+00 variable_3 of experiment_5 has initialValue = 0.9395E-01 variable_1 of experiment_6 has initialValue = 0.5678E+00 variable_2 of experiment_6 has initialValue = 0.5560E+00 variable_3 of experiment_6 has initialValue = 0.5999E+00 variable_1 of experiment_7 has initialValue = 0.6303E+00 variable_2 of experiment_7 has initialValue = 0.9736E-01 variable_3 of experiment_7 has initialValue = 0.1075E+00 variable_1 of experiment_8 has initialValue = 0.3799E+00 variable_2 of experiment_8 has initialValue = 0.6451E+00 variable_3 of experiment_8 has initialValue = 0.9818E-01 // ERROR // error = -L + lambda * K // residual = -L error = 480.953874 residual = 464.953874 end of solution of problem ss_cascade3