format version = 1.0 begin solution of problem ss_cascade3 date = 14-Nov-08 08:03:01 url = http://www.cs.chalmers.se/~dag/identification // Settings for the Gennemark & Wedelin (2007) algorithm randomStarts_ = 8 1 smoothingParameter = 0.2 randomSeed = 4 // ALPHA alpha_1 = 14.0128268 alpha_2 = 2.97771485 alpha_3 = 10.4926787 // BETA beta_1 = 9.3579577 beta_2 = 3.05270014 beta_3 = 13.4597617 // G g has defaultValue = 0 g_1_4 = 0.777993402 g_2_4 = 0.890272034 g_3_2 = 0.431653888 // H h has defaultValue = 0 h_1_1 = 0.397108456 h_1_3 = 0.108781842 h_2_2 = 3.70003152E-11 h_2_3 = 0.60769652 h_3_1 = 0.0143359168 h_3_2 = 0.277802999 h_3_3 = 0.142005264 // INITIAL VALUES variable_1 of experiment_1 has initialValue = 0.1910E+00 variable_2 of experiment_1 has initialValue = 0.4186E+00 variable_3 of experiment_1 has initialValue = 0.1113E+00 variable_1 of experiment_2 has initialValue = 0.9584E-01 variable_2 of experiment_2 has initialValue = 0.6212E+00 variable_3 of experiment_2 has initialValue = 0.5989E+00 variable_1 of experiment_3 has initialValue = 0.9181E-01 variable_2 of experiment_3 has initialValue = 0.5429E+00 variable_3 of experiment_3 has initialValue = 0.5327E+00 variable_1 of experiment_4 has initialValue = 0.4132E+00 variable_2 of experiment_4 has initialValue = 0.5274E+00 variable_3 of experiment_4 has initialValue = 0.9759E-01 variable_1 of experiment_5 has initialValue = 0.6005E+00 variable_2 of experiment_5 has initialValue = 0.3707E+00 variable_3 of experiment_5 has initialValue = 0.9452E-01 variable_1 of experiment_6 has initialValue = 0.5579E+00 variable_2 of experiment_6 has initialValue = 0.5556E+00 variable_3 of experiment_6 has initialValue = 0.6070E+00 variable_1 of experiment_7 has initialValue = 0.6289E+00 variable_2 of experiment_7 has initialValue = 0.9876E-01 variable_3 of experiment_7 has initialValue = 0.1068E+00 variable_1 of experiment_8 has initialValue = 0.3805E+00 variable_2 of experiment_8 has initialValue = 0.5787E+00 variable_3 of experiment_8 has initialValue = 0.9856E-01 // ERROR // error = -L + lambda * K // residual = -L error = 518.449785 residual = 502.449785 end of solution of problem ss_cascade3