format version = 1.0
 
 
 begin solution of problem ss_cascade3                   
 
 date = 14-Nov-08 07:52:32
 url = http://www.cs.chalmers.se/~dag/identification
 
 // Settings for the Gennemark & Wedelin (2007) algorithm
 randomStarts_ =  8  1
 smoothingParameter =   0.2
 randomSeed =  3
 
 
 // ALPHA
 alpha_1 =   11.5719673
 alpha_2 =   2.10902807
 alpha_3 =   3.03903129
 
 // BETA
 beta_1 =   7.75462349
 beta_2 =   1.55762687
 beta_3 =   6.96795987
 
 // G
 g has defaultValue = 0
 g_1_3 =  -0.108883146
 g_1_4 =   0.774170864
 g_2_1 =   0.464307128
 g_3_2 =   0.734331302
 
 // H
 h has defaultValue = 0
 h_1_1 =   0.393845982
 h_2_2 =   0.460164665
 h_3_2 =   0.256765031
 h_3_3 =   0.479069736
 
 
 // INITIAL VALUES
 
variable_1 of experiment_1
has initialValue =     0.1918E+00
 
variable_2 of experiment_1
has initialValue =     0.4738E+00
 
variable_3 of experiment_1
has initialValue =     0.1107E+00
 
variable_1 of experiment_2
has initialValue =     0.9581E-01
 
variable_2 of experiment_2
has initialValue =     0.6161E+00
 
variable_3 of experiment_2
has initialValue =     0.6060E+00
 
variable_1 of experiment_3
has initialValue =     0.9194E-01
 
variable_2 of experiment_3
has initialValue =     0.5719E+00
 
variable_3 of experiment_3
has initialValue =     0.5332E+00
 
variable_1 of experiment_4
has initialValue =     0.4104E+00
 
variable_2 of experiment_4
has initialValue =     0.5842E+00
 
variable_3 of experiment_4
has initialValue =     0.9672E-01
 
variable_1 of experiment_5
has initialValue =     0.5800E+00
 
variable_2 of experiment_5
has initialValue =     0.3847E+00
 
variable_3 of experiment_5
has initialValue =     0.9374E-01
 
variable_1 of experiment_6
has initialValue =     0.5633E+00
 
variable_2 of experiment_6
has initialValue =     0.5620E+00
 
variable_3 of experiment_6
has initialValue =     0.6014E+00
 
variable_1 of experiment_7
has initialValue =     0.6314E+00
 
variable_2 of experiment_7
has initialValue =     0.9685E-01
 
variable_3 of experiment_7
has initialValue =     0.1075E+00
 
variable_1 of experiment_8
has initialValue =     0.3805E+00
 
variable_2 of experiment_8
has initialValue =     0.6533E+00
 
variable_3 of experiment_8
has initialValue =     0.9818E-01
 
  
 
 // ERROR 
 // error = -L + lambda * K
 // residual = -L
 error =   476.721661
 residual =   462.721661
  
 end of solution of problem ss_cascade3