format version = 1.0 begin solution of problem ss_bifeedb1 date = 20100924 1030 url = http://www.odeidentification.org // Settings for the Gennemark & Wedelin (2007) algorithm randomStarts_ = 4 1 smoothingParameter = 1.000000000000000E-008 randomSeed = 4 // VARIABLE 1 reaction_1 of variable_1 has type = GMAterm2Variables has variable X1 = variable_3 has variable X2 = variable_1 has parameter k1 = 0.255504419195D+01 has parameter k2 = -0.799352258776D-01 has parameter k3 = 0.641475802277D+00 reaction_2 of variable_1 has type = GMAterm1Variable has variable X1 = variable_1 has parameter k1 = -0.290529057304D+01 has parameter k2 = 0.100134950661D+01 // VARIABLE 2 reaction_1 of variable_2 has type = GMAterm2Variables has variable X1 = variable_1 has variable X2 = variable_4 has parameter k1 = 0.503922853362D+00 has parameter k2 = 0.202365078043D+01 has parameter k3 = -0.507791755854D-01 reaction_2 of variable_2 has type = GMAterm4Variables has variable X1 = variable_1 has variable X2 = variable_4 has variable X3 = variable_2 has variable X4 = variable_3 has parameter k1 = -0.525521358589D+00 has parameter k2 = 0.129475180988D+01 has parameter k3 = -0.179629799332D+00 has parameter k4 = 0.408432895974D+00 has parameter k5 = -0.654167271613D-02 // VARIABLE 3 reaction_1 of variable_3 has type = GMAterm3Variables has variable X1 = variable_1 has variable X2 = variable_2 has variable X3 = variable_4 has parameter k1 = 0.191965678588D+01 has parameter k2 = 0.832541153297D+00 has parameter k3 = 0.192785044131D+00 has parameter k4 = 0.112656834472D+00 reaction_2 of variable_3 has type = GMAterm3Variables has variable X1 = variable_3 has variable X2 = variable_4 has variable X3 = variable_1 has parameter k1 = -0.229305238932D+01 has parameter k2 = 0.168531129130D+00 has parameter k3 = 0.118409895135D+00 has parameter k4 = 0.354874776904D+00 // VARIABLE 4 reaction_1 of variable_4 has type = GMAterm0Variables has parameter k1 = 0.110915145232D+00 reaction_2 of variable_4 has type = GMAterm1Variable has variable X1 = variable_4 has parameter k1 = -0.493221810681D+00 has parameter k2 = 0.717592822517D+00 // INITIAL VALUES // Perfect data, not required // ERROR // error = -L + lambda * K // residual = -L error = 1.09734740241680 residual = 0.857347407781223 end of solution of problem ss_bifeedb1