format version = 1.0 begin solution of problem ss_bifeedb1 date = 20100924 1021 url = http://www.odeidentification.org // Settings for the Gennemark & Wedelin (2007) algorithm randomStarts_ = 4 1 smoothingParameter = 1.000000000000000E-008 randomSeed = 3 // VARIABLE 1 reaction_1 of variable_1 has type = GMAterm2Variables has variable X1 = variable_3 has variable X2 = variable_1 has parameter k1 = 0.266963139703D+01 has parameter k2 = -0.768897879330D-01 has parameter k3 = 0.646338076727D+00 reaction_2 of variable_1 has type = GMAterm1Variable has variable X1 = variable_1 has parameter k1 = -0.302074254544D+01 has parameter k2 = 0.992550761106D+00 // VARIABLE 2 reaction_1 of variable_2 has type = GMAterm2Variables has variable X1 = variable_1 has variable X2 = variable_4 has parameter k1 = 0.503859345449D+00 has parameter k2 = 0.202341971537D+01 has parameter k3 = -0.505808851082D-01 reaction_2 of variable_2 has type = GMAterm4Variables has variable X1 = variable_1 has variable X2 = variable_4 has variable X3 = variable_2 has variable X4 = variable_3 has parameter k1 = -0.525486219862D+00 has parameter k2 = 0.129414313433D+01 has parameter k3 = -0.179484039871D+00 has parameter k4 = 0.408624028877D+00 has parameter k5 = -0.652845210236D-02 // VARIABLE 3 reaction_1 of variable_3 has type = GMAterm3Variables has variable X1 = variable_1 has variable X2 = variable_2 has variable X3 = variable_4 has parameter k1 = 0.194500100121D+01 has parameter k2 = 0.828763893868D+00 has parameter k3 = 0.189965304052D+00 has parameter k4 = 0.112867103131D+00 reaction_2 of variable_3 has type = GMAterm3Variables has variable X1 = variable_3 has variable X2 = variable_4 has variable X3 = variable_1 has parameter k1 = -0.231726959741D+01 has parameter k2 = 0.166061429544D+00 has parameter k3 = 0.118530781095D+00 has parameter k4 = 0.357979043138D+00 // VARIABLE 4 reaction_1 of variable_4 has type = GMAterm0Variables has parameter k1 = 0.110801631201D+00 reaction_2 of variable_4 has type = GMAterm1Variable has variable X1 = variable_4 has parameter k1 = -0.493494461016D+00 has parameter k2 = 0.718356035776D+00 // INITIAL VALUES // Perfect data, not required // ERROR // error = -L + lambda * K // residual = -L error = 1.09753646370625 residual = 0.857536469070672 end of solution of problem ss_bifeedb1