format version = 1.0 begin solution of problem ss_bifeedb1 date = 20100924 1012 url = http://www.odeidentification.org // Settings for the Gennemark & Wedelin (2007) algorithm randomStarts_ = 4 1 smoothingParameter = 1.000000000000000E-008 randomSeed = 2 // VARIABLE 1 reaction_1 of variable_1 has type = GMAterm2Variables has variable X1 = variable_3 has variable X2 = variable_1 has parameter k1 = 0.266870003491D+01 has parameter k2 = -0.769135127617D-01 has parameter k3 = 0.646299853107D+00 reaction_2 of variable_1 has type = GMAterm1Variable has variable X1 = variable_1 has parameter k1 = -0.301980395685D+01 has parameter k2 = 0.992619539431D+00 // VARIABLE 2 reaction_1 of variable_2 has type = GMAterm2Variables has variable X1 = variable_1 has variable X2 = variable_4 has parameter k1 = 0.503876220982D+00 has parameter k2 = 0.202341289200D+01 has parameter k3 = -0.505777110366D-01 reaction_2 of variable_2 has type = GMAterm4Variables has variable X1 = variable_1 has variable X2 = variable_4 has variable X3 = variable_2 has variable X4 = variable_3 has parameter k1 = -0.525503396237D+00 has parameter k2 = 0.129415558369D+01 has parameter k3 = -0.179477171320D+00 has parameter k4 = 0.408613507289D+00 has parameter k5 = -0.652863185417D-02 // VARIABLE 3 reaction_1 of variable_3 has type = GMAterm3Variables has variable X1 = variable_1 has variable X2 = variable_2 has variable X3 = variable_4 has parameter k1 = 0.194442555288D+01 has parameter k2 = 0.828827567059D+00 has parameter k3 = 0.190022745838D+00 has parameter k4 = 0.112851751930D+00 reaction_2 of variable_3 has type = GMAterm3Variables has variable X1 = variable_3 has variable X2 = variable_4 has variable X3 = variable_1 has parameter k1 = -0.231670794585D+01 has parameter k2 = 0.166111783873D+00 has parameter k3 = 0.118517347465D+00 has parameter k4 = 0.357901138784D+00 // VARIABLE 4 reaction_1 of variable_4 has type = GMAterm0Variables has parameter k1 = 0.110805457979D+00 reaction_2 of variable_4 has type = GMAterm1Variable has variable X1 = variable_4 has parameter k1 = -0.493485151413D+00 has parameter k2 = 0.718330188830D+00 // INITIAL VALUES // Perfect data, not required // ERROR // error = -L + lambda * K // residual = -L error = 1.09753646176790 residual = 0.857536467132323 end of solution of problem ss_bifeedb1