format version = 1.0 begin solution of problem ss_5genes2 date = 14-Nov-08 10:23:26 url = http://www.cs.chalmers.se/~dag/identification // Settings for the Gennemark & Wedelin (2007) algorithm randomStarts_ = 8 1 smoothingParameter = 0.2 randomSeed = 5 // ALPHA alpha_1 = 4.31678729 alpha_2 = 7.40058124 alpha_3 = 5.0305816 alpha_4 = 5.26244401 alpha_5 = 10.0064317 // BETA beta_1 = 6.89742155 beta_2 = 8.79442814 beta_3 = 7.1062934 beta_4 = 9.42757951 beta_5 = 9.45181324 // G g has defaultValue = 0 g_1_3 = 0.624232858 g_1_5 = -1.04828512 g_2_1 = 2.22643344 g_2_3 = -1.87969976 g_2_4 = 0.533374749 g_3_2 = -1.32920253 g_4_3 = 1.54087274 g_4_5 = -1.03029355 g_5_4 = 1.17614234 // H h has defaultValue = 0 h_1_1 = 0.775723638 h_2_2 = 3. h_2_3 = -1.46285224 h_3_2 = -1.1354608 h_3_3 = 3. h_4_4 = 1.67059029 h_4_5 = 1.23252893 h_5_5 = 0.967574684 // INITIAL VALUES variable_1 of experiment_1 has initialValue = 0.6078E+00 variable_2 of experiment_1 has initialValue = 0.1146E+00 variable_3 of experiment_1 has initialValue = 0.1506E+00 variable_4 of experiment_1 has initialValue = 0.1159E+00 variable_5 of experiment_1 has initialValue = 0.1848E+00 variable_1 of experiment_2 has initialValue = 0.8852E-01 variable_2 of experiment_2 has initialValue = 0.8754E+00 variable_3 of experiment_2 has initialValue = 0.1391E+00 variable_4 of experiment_2 has initialValue = 0.1763E+00 variable_5 of experiment_2 has initialValue = 0.2186E+00 variable_1 of experiment_3 has initialValue = 0.1230E+00 variable_2 of experiment_3 has initialValue = 0.1279E+00 variable_3 of experiment_3 has initialValue = 0.6571E+00 variable_4 of experiment_3 has initialValue = 0.1734E+00 variable_5 of experiment_3 has initialValue = 0.1732E+00 variable_1 of experiment_4 has initialValue = 0.1063E+00 variable_2 of experiment_4 has initialValue = 0.1139E+00 variable_3 of experiment_4 has initialValue = 0.1082E+00 variable_4 of experiment_4 has initialValue = 0.7163E+00 variable_5 of experiment_4 has initialValue = 0.2027E+00 variable_1 of experiment_5 has initialValue = 0.8634E-01 variable_2 of experiment_5 has initialValue = 0.1158E+00 variable_3 of experiment_5 has initialValue = 0.1534E+00 variable_4 of experiment_5 has initialValue = 0.1664E+00 variable_5 of experiment_5 has initialValue = 0.6816E+00 variable_1 of experiment_6 has initialValue = 0.6884E+00 variable_2 of experiment_6 has initialValue = 0.6489E+00 variable_3 of experiment_6 has initialValue = 0.1822E+00 variable_4 of experiment_6 has initialValue = 0.1403E+00 variable_5 of experiment_6 has initialValue = 0.7573E+00 variable_1 of experiment_7 has initialValue = 0.1063E+00 variable_2 of experiment_7 has initialValue = 0.6801E+00 variable_3 of experiment_7 has initialValue = 0.6903E+00 variable_4 of experiment_7 has initialValue = 0.1728E+00 variable_5 of experiment_7 has initialValue = 0.1969E+00 variable_1 of experiment_8 has initialValue = 0.1120E+00 variable_2 of experiment_8 has initialValue = 0.1291E+00 variable_3 of experiment_8 has initialValue = 0.7370E+00 variable_4 of experiment_8 has initialValue = 0.6433E+00 variable_5 of experiment_8 has initialValue = 0.1893E+00 variable_1 of experiment_9 has initialValue = 0.1110E+00 variable_2 of experiment_9 has initialValue = 0.1168E+00 variable_3 of experiment_9 has initialValue = 0.1368E+00 variable_4 of experiment_9 has initialValue = 0.6292E+00 variable_5 of experiment_9 has initialValue = 0.6155E+00 variable_1 of experiment_10 has initialValue = 0.6634E+00 variable_2 of experiment_10 has initialValue = 0.1064E+00 variable_3 of experiment_10 has initialValue = 0.1382E+00 variable_4 of experiment_10 has initialValue = 0.1715E+00 variable_5 of experiment_10 has initialValue = 0.7136E+00 // ERROR // error = -L + lambda * K // residual = -L error = 212.186883 residual = 185.186883 end of solution of problem ss_5genes2