format version = 1.0 begin solution of problem ss_5genes2 date = 14-Nov-08 09:50:47 url = http://www.cs.chalmers.se/~dag/identification // Settings for the Gennemark & Wedelin (2007) algorithm randomStarts_ = 8 1 smoothingParameter = 0.2 randomSeed = 3 // ALPHA alpha_1 = 3.70843357 alpha_2 = 7.47875767 alpha_3 = 4.99409998 alpha_4 = 4.49332612 alpha_5 = 10.3118703 // BETA beta_1 = 6.51096901 beta_2 = 8.40401492 beta_3 = 7.01612365 beta_4 = 9.02398394 beta_5 = 9.70254195 // G g has defaultValue = 0 g_1_3 = 0.649951614 g_1_5 = -1.1338642 g_2_1 = 2.25685313 g_2_3 = -1.8774517 g_2_4 = 0.522940282 g_3_2 = -1.33927996 g_4_3 = 1.44984234 g_4_5 = -1.09783377 g_5_4 = 1.03150967 // H h has defaultValue = 0 h_1_1 = 0.993819498 h_2_2 = 2.88135468 h_2_3 = -1.44371684 h_3_2 = -1.15046158 h_3_3 = 3. h_4_3 = -3. h_4_4 = 3. h_4_5 = 2.32671176 h_5_5 = 0.874460678 // INITIAL VALUES variable_1 of experiment_1 has initialValue = 0.6071E+00 variable_2 of experiment_1 has initialValue = 0.1144E+00 variable_3 of experiment_1 has initialValue = 0.1504E+00 variable_4 of experiment_1 has initialValue = 0.1153E+00 variable_5 of experiment_1 has initialValue = 0.1834E+00 variable_1 of experiment_2 has initialValue = 0.8853E-01 variable_2 of experiment_2 has initialValue = 0.8744E+00 variable_3 of experiment_2 has initialValue = 0.1388E+00 variable_4 of experiment_2 has initialValue = 0.1757E+00 variable_5 of experiment_2 has initialValue = 0.2178E+00 variable_1 of experiment_3 has initialValue = 0.1227E+00 variable_2 of experiment_3 has initialValue = 0.1277E+00 variable_3 of experiment_3 has initialValue = 0.6575E+00 variable_4 of experiment_3 has initialValue = 0.1738E+00 variable_5 of experiment_3 has initialValue = 0.1724E+00 variable_1 of experiment_4 has initialValue = 0.1058E+00 variable_2 of experiment_4 has initialValue = 0.1139E+00 variable_3 of experiment_4 has initialValue = 0.1086E+00 variable_4 of experiment_4 has initialValue = 0.7303E+00 variable_5 of experiment_4 has initialValue = 0.2017E+00 variable_1 of experiment_5 has initialValue = 0.8641E-01 variable_2 of experiment_5 has initialValue = 0.1159E+00 variable_3 of experiment_5 has initialValue = 0.1533E+00 variable_4 of experiment_5 has initialValue = 0.1686E+00 variable_5 of experiment_5 has initialValue = 0.6767E+00 variable_1 of experiment_6 has initialValue = 0.6832E+00 variable_2 of experiment_6 has initialValue = 0.6471E+00 variable_3 of experiment_6 has initialValue = 0.1854E+00 variable_4 of experiment_6 has initialValue = 0.1413E+00 variable_5 of experiment_6 has initialValue = 0.7493E+00 variable_1 of experiment_7 has initialValue = 0.1061E+00 variable_2 of experiment_7 has initialValue = 0.6805E+00 variable_3 of experiment_7 has initialValue = 0.6886E+00 variable_4 of experiment_7 has initialValue = 0.1729E+00 variable_5 of experiment_7 has initialValue = 0.1958E+00 variable_1 of experiment_8 has initialValue = 0.1119E+00 variable_2 of experiment_8 has initialValue = 0.1292E+00 variable_3 of experiment_8 has initialValue = 0.7382E+00 variable_4 of experiment_8 has initialValue = 0.6434E+00 variable_5 of experiment_8 has initialValue = 0.1911E+00 variable_1 of experiment_9 has initialValue = 0.1114E+00 variable_2 of experiment_9 has initialValue = 0.1175E+00 variable_3 of experiment_9 has initialValue = 0.1316E+00 variable_4 of experiment_9 has initialValue = 0.7637E+00 variable_5 of experiment_9 has initialValue = 0.6327E+00 variable_1 of experiment_10 has initialValue = 0.6642E+00 variable_2 of experiment_10 has initialValue = 0.1064E+00 variable_3 of experiment_10 has initialValue = 0.1384E+00 variable_4 of experiment_10 has initialValue = 0.1732E+00 variable_5 of experiment_10 has initialValue = 0.7106E+00 // ERROR // error = -L + lambda * K // residual = -L error = 211.010885 residual = 183.010885 end of solution of problem ss_5genes2