format version = 1.0 begin solution of problem ss_5genes2 date = 14-Nov-08 09:17:13 url = http://www.cs.chalmers.se/~dag/identification // Settings for the Gennemark & Wedelin (2007) algorithm randomStarts_ = 8 1 smoothingParameter = 0.2 randomSeed = 1 // ALPHA alpha_1 = 5.00552194 alpha_2 = 7.42174995 alpha_3 = 5.053447 alpha_4 = 5.37716117 alpha_5 = 9.56934067 // BETA beta_1 = 7.58778722 beta_2 = 8.34594298 beta_3 = 7.17374404 beta_4 = 9.55698049 beta_5 = 9.01850495 // G g has defaultValue = 0 g_1_3 = 0.621745049 g_1_5 = -0.987130265 g_2_1 = 2.31086543 g_2_3 = -0.911150608 g_3_2 = -1.28898746 g_4_3 = 1.51053036 g_4_5 = -1.01865714 g_5_4 = 1.23221571 // H h has defaultValue = 0 h_1_1 = 0.651251179 h_2_2 = 3. h_2_3 = -1.4650052 h_3_2 = -1.08787372 h_3_3 = 3. h_4_4 = 1.58923461 h_4_5 = 1.20364682 h_5_5 = 1.00651289 // INITIAL VALUES variable_1 of experiment_1 has initialValue = 0.5849E+00 variable_2 of experiment_1 has initialValue = 0.1133E+00 variable_3 of experiment_1 has initialValue = 0.1481E+00 variable_4 of experiment_1 has initialValue = 0.1174E+00 variable_5 of experiment_1 has initialValue = 0.1869E+00 variable_1 of experiment_2 has initialValue = 0.8870E-01 variable_2 of experiment_2 has initialValue = 0.8698E+00 variable_3 of experiment_2 has initialValue = 0.1396E+00 variable_4 of experiment_2 has initialValue = 0.1755E+00 variable_5 of experiment_2 has initialValue = 0.2172E+00 variable_1 of experiment_3 has initialValue = 0.1227E+00 variable_2 of experiment_3 has initialValue = 0.1263E+00 variable_3 of experiment_3 has initialValue = 0.6581E+00 variable_4 of experiment_3 has initialValue = 0.1737E+00 variable_5 of experiment_3 has initialValue = 0.1745E+00 variable_1 of experiment_4 has initialValue = 0.1064E+00 variable_2 of experiment_4 has initialValue = 0.1150E+00 variable_3 of experiment_4 has initialValue = 0.1085E+00 variable_4 of experiment_4 has initialValue = 0.7103E+00 variable_5 of experiment_4 has initialValue = 0.2017E+00 variable_1 of experiment_5 has initialValue = 0.8637E-01 variable_2 of experiment_5 has initialValue = 0.1148E+00 variable_3 of experiment_5 has initialValue = 0.1533E+00 variable_4 of experiment_5 has initialValue = 0.1674E+00 variable_5 of experiment_5 has initialValue = 0.6858E+00 variable_1 of experiment_6 has initialValue = 0.6925E+00 variable_2 of experiment_6 has initialValue = 0.6565E+00 variable_3 of experiment_6 has initialValue = 0.1826E+00 variable_4 of experiment_6 has initialValue = 0.1394E+00 variable_5 of experiment_6 has initialValue = 0.7543E+00 variable_1 of experiment_7 has initialValue = 0.1061E+00 variable_2 of experiment_7 has initialValue = 0.6804E+00 variable_3 of experiment_7 has initialValue = 0.6900E+00 variable_4 of experiment_7 has initialValue = 0.1731E+00 variable_5 of experiment_7 has initialValue = 0.1987E+00 variable_1 of experiment_8 has initialValue = 0.1120E+00 variable_2 of experiment_8 has initialValue = 0.1303E+00 variable_3 of experiment_8 has initialValue = 0.7375E+00 variable_4 of experiment_8 has initialValue = 0.6428E+00 variable_5 of experiment_8 has initialValue = 0.1889E+00 variable_1 of experiment_9 has initialValue = 0.1111E+00 variable_2 of experiment_9 has initialValue = 0.1173E+00 variable_3 of experiment_9 has initialValue = 0.1367E+00 variable_4 of experiment_9 has initialValue = 0.6292E+00 variable_5 of experiment_9 has initialValue = 0.6192E+00 variable_1 of experiment_10 has initialValue = 0.6454E+00 variable_2 of experiment_10 has initialValue = 0.1088E+00 variable_3 of experiment_10 has initialValue = 0.1390E+00 variable_4 of experiment_10 has initialValue = 0.1690E+00 variable_5 of experiment_10 has initialValue = 0.7222E+00 // ERROR // error = -L + lambda * K // residual = -L error = 212.63467 residual = 186.63467 end of solution of problem ss_5genes2