format version = 1.0
 
 
 begin solution of problem pe_ss_feedf1                  
 
 date = 20100925 2214
 url = http://www.odeidentification.org
 
 // Settings for the Gennemark & Wedelin (2007) algorithm
 randomStarts_ =            4             1
 smoothingParameter =   1.000000000000000E-008
 randomSeed =            5
 
 
 
 // VARIABLE            3
  
reaction_1 of variable_3
has type = GMAterm1Variable              
has variable X1 = variable_3
has parameter k1 =   0.100340593161D+02
has parameter k2 =  -0.200178301742D-01
  
reaction_2 of variable_3
has type = GMAterm1Variable              
has variable X1 = variable_3
has parameter k1 =  -0.103560569850D+02
has parameter k2 =   0.452904359188D-03
  
 
 
 // VARIABLE            4
  
reaction_1 of variable_4
has type = GMAterm1Variable              
has variable X1 = variable_3
has parameter k1 =   0.164315086808D+01
has parameter k2 =  -0.794972082924D-03
  
reaction_2 of variable_4
has type = GMAterm1Variable              
has variable X1 = variable_4
has parameter k1 =  -0.205653586844D+01
has parameter k2 =   0.126399557542D+00
  
 
 
 // VARIABLE            5
  
reaction_1 of variable_5
has type = GMAterm2Variables             
has variable X1 = variable_3
has variable X2 = variable_4
has parameter k1 =   0.423375799435D+01
has parameter k2 =   0.615987153324D-01
has parameter k3 =   0.593849313154D-01
  
reaction_2 of variable_5
has type = GMAterm1Variable              
has variable X1 = variable_5
has parameter k1 =  -0.365923944470D+01
has parameter k2 =   0.677389147978D-01
  
 
 
 // VARIABLE            6
  
reaction_1 of variable_6
has type = GMAterm1Variable              
has variable X1 = variable_5
has parameter k1 =   0.400000000000D+02
has parameter k2 =   0.594227807070D-02
  
reaction_2 of variable_6
has type = GMAterm1Variable              
has variable X1 = variable_6
has parameter k1 =  -0.399994559344D+02
has parameter k2 =   0.594311218199D-02
  
 
 
 // INITIAL VALUES
 // Perfect data, not required
 
 
 // ERROR 
 // residual = -L
 residual =   0.100432213491775     
  
 end of solution of problem pe_ss_feedf1