format version = 1.0
 
 
 begin solution of problem pe_ss_bifeedb1                
 
 date = 20100925 2217
 url = http://www.odeidentification.org
 
 // Settings for the Gennemark & Wedelin (2007) algorithm
 randomStarts_ =            4             1
 smoothingParameter =   1.000000000000000E-008
 randomSeed =            4
 
 
 
 // VARIABLE            1
  
reaction_1 of variable_1
has type = GMAterm1Variable              
has variable X1 = variable_3
has parameter k1 =   0.282684164953D+00
has parameter k2 =  -0.405230557568D+00
  
reaction_2 of variable_1
has type = GMAterm1Variable              
has variable X1 = variable_1
has parameter k1 =  -0.545062148385D+00
has parameter k2 =   0.187996091987D+01
  
 
 
 // VARIABLE            2
  
reaction_1 of variable_2
has type = GMAterm2Variables             
has variable X1 = variable_1
has variable X2 = variable_4
has parameter k1 =   0.347863484694D+01
has parameter k2 =   0.169297442728D+01
has parameter k3 =   0.207013889626D-01
  
reaction_2 of variable_2
has type = GMAterm2Variables             
has variable X1 = variable_1
has variable X2 = variable_2
has parameter k1 =  -0.351961573190D+01
has parameter k2 =   0.156442157044D+01
has parameter k3 =   0.689086585898D-01
  
 
 
 // VARIABLE            3
  
reaction_1 of variable_3
has type = GMAterm2Variables             
has variable X1 = variable_1
has variable X2 = variable_2
has parameter k1 =   0.628020871755D+00
has parameter k2 =   0.148723800719D+01
has parameter k3 =   0.607482205689D+00
  
reaction_2 of variable_3
has type = GMAterm1Variable              
has variable X1 = variable_3
has parameter k1 =  -0.107093837306D+01
has parameter k2 =   0.537573868430D+00
  
 
 
 // VARIABLE            4
  
reaction_1 of variable_4
has type = GMAterm1Variable              
has variable X1 = variable_1
has parameter k1 =   0.136605937697D+00
has parameter k2 =   0.432993977049D-02
  
reaction_2 of variable_4
has type = GMAterm1Variable              
has variable X1 = variable_4
has parameter k1 =  -0.451060603584D+00
has parameter k2 =   0.573856379697D+00
  
 
 
 // INITIAL VALUES
 // Perfect data, not required
 
 
 // ERROR 
 // residual = -L
 residual =    1.76672878445882     
  
 end of solution of problem pe_ss_bifeedb1