format version = 1.0
 
 
 begin solution of problem pe_ss_bifeedb1                
 
 date = 20100925 2217
 url = http://www.odeidentification.org
 
 // Settings for the Gennemark & Wedelin (2007) algorithm
 randomStarts_ =            4             1
 smoothingParameter =   1.000000000000000E-008
 randomSeed =            3
 
 
 
 // VARIABLE            1
  
reaction_1 of variable_1
has type = GMAterm1Variable              
has variable X1 = variable_3
has parameter k1 =   0.282684678917D+00
has parameter k2 =  -0.405230091540D+00
  
reaction_2 of variable_1
has type = GMAterm1Variable              
has variable X1 = variable_1
has parameter k1 =  -0.545062729170D+00
has parameter k2 =   0.187995922488D+01
  
 
 
 // VARIABLE            2
  
reaction_1 of variable_2
has type = GMAterm2Variables             
has variable X1 = variable_1
has variable X2 = variable_4
has parameter k1 =   0.347917611376D+01
has parameter k2 =   0.169296176553D+01
has parameter k3 =   0.206980734195D-01
  
reaction_2 of variable_2
has type = GMAterm2Variables             
has variable X1 = variable_1
has variable X2 = variable_2
has parameter k1 =  -0.352015636735D+01
has parameter k2 =   0.156442991078D+01
has parameter k3 =   0.688974740076D-01
  
 
 
 // VARIABLE            3
  
reaction_1 of variable_3
has type = GMAterm2Variables             
has variable X1 = variable_1
has variable X2 = variable_2
has parameter k1 =   0.628020570484D+00
has parameter k2 =   0.148723930245D+01
has parameter k3 =   0.607482694483D+00
  
reaction_2 of variable_3
has type = GMAterm1Variable              
has variable X1 = variable_3
has parameter k1 =  -0.107093815968D+01
has parameter k2 =   0.537574202551D+00
  
 
 
 // VARIABLE            4
  
reaction_1 of variable_4
has type = GMAterm1Variable              
has variable X1 = variable_1
has parameter k1 =   0.136609287825D+00
has parameter k2 =   0.433654535985D-02
  
reaction_2 of variable_4
has type = GMAterm1Variable              
has variable X1 = variable_4
has parameter k1 =  -0.451058495986D+00
has parameter k2 =   0.573842223147D+00
  
 
 
 // INITIAL VALUES
 // Perfect data, not required
 
 
 // ERROR 
 // residual = -L
 residual =    1.76672878822425     
  
 end of solution of problem pe_ss_bifeedb1