format version = 1.0
 
 
 begin solution of problem pe_ss_bifeedb1                
 
 date = 20100925 2216
 url = http://www.odeidentification.org
 
 // Settings for the Gennemark & Wedelin (2007) algorithm
 randomStarts_ =            4             1
 smoothingParameter =   1.000000000000000E-008
 randomSeed =            1
 
 
 
 // VARIABLE            1
  
reaction_1 of variable_1
has type = GMAterm1Variable              
has variable X1 = variable_3
has parameter k1 =   0.283679441520D+00
has parameter k2 =  -0.404266918158D+00
  
reaction_2 of variable_1
has type = GMAterm1Variable              
has variable X1 = variable_1
has parameter k1 =  -0.546134437880D+00
has parameter k2 =   0.187660859481D+01
  
 
 
 // VARIABLE            2
  
reaction_1 of variable_2
has type = GMAterm2Variables             
has variable X1 = variable_1
has variable X2 = variable_4
has parameter k1 =   0.176065903868D+02
has parameter k2 =   0.162655215158D+01
has parameter k3 =   0.397985263842D-02
  
reaction_2 of variable_2
has type = GMAterm2Variables             
has variable X1 = variable_1
has variable X2 = variable_2
has parameter k1 =  -0.176450780355D+02
has parameter k2 =   0.160200491827D+01
has parameter k3 =   0.131558029774D-01
  
 
 
 // VARIABLE            3
  
reaction_1 of variable_3
has type = GMAterm2Variables             
has variable X1 = variable_1
has variable X2 = variable_2
has parameter k1 =   0.628069105599D+00
has parameter k2 =   0.148744897753D+01
has parameter k3 =   0.607812108128D+00
  
reaction_2 of variable_3
has type = GMAterm1Variable              
has variable X1 = variable_3
has parameter k1 =  -0.107066176773D+01
has parameter k2 =   0.537494854753D+00
  
 
 
 // VARIABLE            4
  
reaction_1 of variable_4
has type = GMAterm1Variable              
has variable X1 = variable_1
has parameter k1 =   0.145979432288D+00
has parameter k2 =   0.203649256137D-02
  
reaction_2 of variable_4
has type = GMAterm1Variable              
has variable X1 = variable_4
has parameter k1 =  -0.446374555813D+00
has parameter k2 =   0.536789488986D+00
  
 
 
 // INITIAL VALUES
 // Perfect data, not required
 
 
 // ERROR 
 // residual = -L
 residual =    1.77053189123477     
  
 end of solution of problem pe_ss_bifeedb1