O(34x + x²) = O(x²) O(1x + 2x + 3x + 4x + 5x + 6x + 7x) = O(x) O(10^4000 x + 0.005 x² + 103/x³) = O(x²) 103/x³ approaches 0 as x approaches infinity. O(10 log₂ x + 2 log₁₀ x) = O(log x) the base of the logarithm is irrelevant in big-O notation since using the logarithm law we have log₂ N = log₂ b · log_b N for any constant b, and since log₂ b is a constant we have O(log₂ N) = O(log_b N) for any constant b O(2^x + 10^x) = O(10^x) 10^x and 2^x are different as they do not differ by a constant. 10^x / 2^x = 5^x and so O(10^x) ≠ O(2^x). O((x–2) (x–1) x) = O(x³)